GRE Math Test – Solutions
Click the link immediately below to view the GRE Verbal Diagnostic test.
Test Questions
1. If x and y are both prime and greater than 2, then which of the following CANNOT be a divisor of xy?
(A) 2
(B) 3
(C) 11
(D) 15
(E) 17
Correct Answer: (A)
Solution: Since x and y are prime and greater than 2, xy is the product of two odd numbers and is therefore odd. Hence, 2 cannot be a divisor of xy. The answer is (A).
2.
| Column A | x and y are integers greater than 1. | Column B |
| 2(x + y) | 2xy |
Correct Answer: (D)
Solution: If x = y = 2, then 2(x + y) = 2(2 + 2) = 8 and 2xy = (2)(2)(2) = 8. In this case, the columns are equal. For all other choices of x and y, Column B is greater. (You should check a few cases.) Hence, we have a double case, and therefore the answer is (D).
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3. In the figure shown, y =
(A) 75
(B) 76
(C) 77
(D) 78
(E) 79
Correct Answer: (D)
Solution: OS and OT are equal since they are radii of the circle. Hence, Triangle SOT is isosceles. Therefore, S = T = 51. Recalling that the angle sum of a triangle is 180 degrees, we get S + T + y = 51 + 51 + y = 180. Solving for y gives y = 78. The answer is (D).
4. If x = 3y = 4z, which of the following must equal 6x?
I. 18y
II. 3y + 20z
III. (4y + 10z)/3
(A) I only (B) II only
(C) III only
(D) I and II only
(E) I and III only
Correct Answer: (D)
Solution: The equation x = 3y = 4z contains three equations:
x = 3y
3y = 4z
x = 4z
Multiplying both sides of the equation x = 3y by 6 gives 6x = 18y. Hence, Statement I is true. This eliminates (B) and (C). Next, 3y + 20z = 3y + 5(4z) . Substituting x for 3y and for 4z in this equation gives
3y + 20z = 3y + 5(4z) = x + 5x = 6x
Hence, Statement II is true. This eliminates (A) and (E). Hence, by process of elimination, the answer is (D).
5. The average of four numbers is 20. If one of the numbers is removed, the average of the remaining numbers is 15. What number was removed?
(A) 10
(B) 15
(C) 30
(D) 35
(E) 45
Correct Answer: (D)
Solution: Let the four numbers be a, b, c, and d. Since their average is 20, we get
(a + b + c + d)/4 = 20
Let d be the number that is removed. Since the average of the remaining numbers is 15, we get
(a + b + c)/3 = 15
Solving for a + b + c yields
a + b + c = 45
Substituting this into the first equation yields
(45 + d)/4 = 20
Multiplying both sides of this equation by 4 yields
45 + d = 80
Subtracting 45 from both sides of this equation yields
d = 35
The answer is (D).
6. The ratio of two numbers is 10 and their difference is 18. What is the value of the smaller number?
(A) 2
(B) 5
(C) 10
(D) 21
(E) 27
Correct Answer: (A)
Solution: Let x and y denote the numbers. Then x/y = 10 and x – y = 18. Solving the first equation for x and plugging it into the second equation yields
10y – y = 18
9y = 18
y = 2
Plugging this into the equation x – y = 18 yields x = 20. Hence, y is the smaller number. The answer is (A).
7. If 3y + 5 = 7x, then 21y – 49x =
(A) -40
(B) -35
(C) -10
(D) 0
(E) 15
Correct Answer: (B)
Solution: First, interchanging 5 and 7x in the expression 3y + 5 = 7x yields 3y – 7x = -5. Next, factoring 21y – 49x yields
21y – 49x =
7(3y) – 7(7x) =
7(3y – 7x) =
7(-5) = since 3y – 7x = -5
-35
The answer is (B).
8. Seven years ago, Scott was 3 times as old as Kathy was at that time. If Scott is now 5 years older than Kathy, how old is Scott?
(A) 12 1/2
(B) 13
(C) 13 1/2
(D) 14
(E) 14 1/2
Correct Answer: (E)
Solution: Let S be Scott’s age and K be Kathy’s age. Then translating the sentence “If Scott is now 5 years older than Kathy, how old is Scott” into an equation yields
S = K + 5
Now, Scott’s age 7 years ago can be represented as S = -7, and Kathy’s age can be represented as K = -7. Then translating the sentence “Seven years ago, Scott was 3 times as old as Kathy was at that time” into an equation yields
S – 7 = 3(K – 7)
Combining this equation with S = K + 5 yields the system:
S – 7 = 3(K – 7)
S = K + 5
Solving this system gives 14 1/2. The answer is (E).
